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Solving for the inverse of a function in R

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Is there any way for R to solve for the inverse of a given single variable function? The motivation is for me to later tell R to use a vector of values as inputs of the inverse function so that it can spit out the inverse function values.

For instance, I have the function y(x) = x^2, the inverse is y = sqrt(x). Is there a way R can solve for the inverse function?

I looked up uniroot(), but I am not solving for the zero of a function.

Any suggestions would be helpful.

Thanks!

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crazian Avatar asked Apr 10 '12 00:04

crazian


2 Answers

What kind of inverse are you finding? If you're looking for a symbolic inverse (e.g., a function y that is identically equal to sqrt(x)) you're going to have to use a symbolic system. Look at ryacas for an R library to connect with a computer algebra system that can likely compute inverses, Yacas.

Now, if you need only to compute point-wise inverses, you can define your function in terms of uniroot as you've written:

> inverse = function (f, lower = -100, upper = 100) {    function (y) uniroot((function (x) f(x) - y), lower = lower, upper = upper)[1] }  > square_inverse = inverse(function (x) x^2, 0.1, 100)  > square_inverse(4) [1] 1.999976 

For a given y and f(x), this will compute x such that f(x) = y, also known as the inverse.

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Mike Axiak Avatar answered Sep 17 '22 01:09

Mike Axiak


I cannot comment as my reputation is too low. I am a newbie to R, and it took me a while to understand Mike's code as I was not used to the way functions are defined in his answer. Below is Mike's code in a longer, but (to me) easier readable notation:

inverse <- function(f, lower, upper){   function(y){     uniroot(function(x){f(x) - y}, lower = lower, upper = upper, tol=1e-3)[1]   } } square_inverse <- inverse(function(x){x^2}, 0.1, 100) square_inverse(4) 

I hope it helps others newbies as well.

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Jan H. Avatar answered Sep 20 '22 01:09

Jan H.