Smallest number in array and its position

Question

What I am trying to achieve is to find smallest number in array and its initial position. Here's an example what it should do:

temp = new Array();
temp[0] = 43;
temp[1] = 3;
temp[2] = 23;

So in the end I should know number 3 and position 1. I also had a look here: Obtain smallest value from array in Javascript?, but this way does not give me a number position in the array. Any tips, or code snippets are appreciated.

Answer 1

Just loop through the array and look for the lowest number:

var index = 0;
var value = temp[0];
for (var i = 1; i < temp.length; i++) {
  if (temp[i] < value) {
    value = temp[i];
    index = i;
  }
}

Now value contains the lowest value, and index contains the lowest index where there is such a value in the array.

Answer 2

You want to use indexOf

http://www.w3schools.com/jsref/jsref_indexof_array.asp

Using the code that you had before, from the other question:

temp = new Array();
temp[0] = 43;
temp[1] = 3;
temp[2] = 23;

Array.min = function( array ){
    return Math.min.apply( Math, array );
};

var value = temp.min;
var key = temp.indexOf(value);