Smallest number in 2d array not working correctly

Question

I am trying to find the smallest number in the array.
When i execute this code, it shows "23" as smallest.
I am not able to find the mistake, can anyone help me out?

Here is the code to find the smallest number in 2d array which i tried.
When i execute this code, it shows "23" as smallest.
I am not able to find the mistake.

public class arraymin {
    public static void main(String args[])
    {
        int arr1[][]=new int[][]{{23,32,10,44},{44,33,22,11}};
        int minvalue=arr1[0][0];
        for(int i=0;i<arr1.length;i++)
        {
            for(int j=0;j<arr1.length;j++)
            {
                if(arr1[i][j]<minvalue)
                {
                   minvalue= arr1[i][j];
                }
            } 
        }
        System.out.println("Min Value is: "+minvalue);
    }
}

Answer 1

You inner loop should be

for(int j=0;j<arr1[i].length;j++)

since the number of columns is different than the number of rows.

And the full code:

public class arraymin {
  public static void main(String args[])
  {
    int arr1[][]=new int[][]{{23,32,10,44},{44,33,22,11}};
    int minvalue=arr1[0][0];
    for(int i=0;i<arr1.length;i++)
    {
        for(int j=0;j<arr1[i].length;j++)
        {
            if(arr1[i][j]<minvalue)
            {
               minvalue= arr1[i][j];
            }
        } 
    }
    System.out.println("Min Value is: "+minvalue);
  }
}

Your current code only checks the first two columns in each row, so out of 23,32,44 and 33, 23 is the smallest number.

Answer 2

In your inner loop, you use:

for(int j=0;j<arr1.length;j++)

but those arrays are longer, so it will only look at the first two elements of those arrays, making 23 indeed the smallest.

Change the above to:

for (int j = 0; j < arr1[i].length; j++)