My types:
data Test = Test {
a :: Int,
b :: Int
} deriving (Show)
My parser:
testParser :: Parser Test
testParser = do
a <- decimal
tab
b <- decimal
return $ Test a b
tab = char '\t'
Now in order to skip the first line, I do something like this:
import qualified System.IO as IO
parser :: Parser Test
parser = manyTill anyChar endOfLine *> testParser
main = IO.withFile testFile IO.ReadMode $ \testHandle -> runEffect $
for (parsed (parser <* endOfLine) (fromHandle testHandle)) (lift . print)
But the above parser
function makes every alternate link skip (which is obvious). How to only skip the first line in such a way that it works with Pipes ecosystem (Producer
should produce a single Test
value.) This is one obvious solution which I don't want (the below code will only work if I modify testParser to read newlines) because it returns the entire [Test]
instead of a single value:
tests :: Parser [Test]
tests = manyTill anyChar endOfLine *>
many1 testParser
Any ideas to tackle this problem ?
You can drop the first line efficiently in constant space like this:
import Lens.Family (over)
import Pipes.Group (drops)
import Pipes.ByteString (lines)
import Prelude hiding (lines)
dropLine :: Monad m => Producer ByteString m r -> Producer ByteString m r
dropLine = over lines (drops 1)
You can apply dropLine
to your Producer
before you parse the Producer
, like this:
main = IO.withFile testFile IO.ReadMode $ \testHandle -> runEffect $
let p = dropLine (fromHandle testHandle)
for (parsed (parser <* endOfLine) p) (lift . print)
If the first line doesn't contain any valid Test
, you can use Either () Test
in order to handle it:
parserEither :: Parser (Either () Test)
parserEither = Right <$> testParser <* endOfLine
<|> Left <$> (manyTill anyChar endOfLine *> pure ())
After this you can use the functions provided by Pipes.Prelude
to get rid of the first result (and additionally of all non-parseable lines):
producer p = parsed parserEither p
>-> P.drop 1
>-> P.filter (either (const False) (const True))
>-> P.map (\(Right x) -> x)
main = IO.withFile testFile IO.ReadMode $ \testHandle -> runEffect $
for (producer (fromHandle testHandle)) (lift . print)
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With