single function to dismiss all open view controllers

Question

I have an app which is a single view application. I have a navigation controller linked up to all child controllers from the root view controller.

In each child controller, I have a logout button. I'm wondering if I can have a single function I can call which will dismiss all the controllers which have been open along along the way, no matter which controller was currently open when the user presses logout?

My basic start:

func tryLogout(){      self.dismissViewControllerAnimated(true, completion: nil)      let navigationController = UINavigationController(rootViewController: UIStoryboard(name: "Main", bundle: nil).instantiateViewControllerWithIdentifier("LoginViewController") )      self.presentViewController(navigationController, animated: true, completion: nil) } 

I am looking for the most memory efficient way of carrying out this task. I will put my logout function in a separate utils file, but then I can't use self. And I still have the issue of knowing which controllers to dismiss dynamically.

Update Pop to root view controller has been suggested. So my attempt is something like:

func tryLogout(ViewController : UIViewController){      print("do something")      dispatch_async(dispatch_get_main_queue(), {          ViewController.navigationController?.popToRootViewControllerAnimated(true)          return      })  } 

Would this be the best way to achieve what I'm after?

Answer 1

You can call :

self.view.window!.rootViewController?.dismiss(animated: false, completion: nil) 

Should dismiss all view controllers above the root view controller.

Answer 2

Updated answer for Swift 4 and swift 5

UIApplication.shared.keyWindow?.rootViewController?.dismiss(animated: true, completion: nil) 

and when you use navigationController

self.navigationController?.popToRootViewController(animated: true)