simple loop over files in some directory makefile

Question

I can easily print all the files inside some directory from bash:

$ cat go.sh
BASEDIR=~/Downloads
MYDIR=${BASEDIR}/ddd
for f in $(ls ${MYDIR}); do echo $f; done

$ ./go.sh
m.txt
d.txt

When I try to do a similar thing from makefile it doesn't work well:

$ cat makefile
BASEDIR = ${HOME}/Downloads
MYDIR = ${BASEDIR}/ddd
all:
    for f in $(ls ${MYDIR}); do echo ${f}; done

$ make
for f in ; do echo ; done

And here is another trial that doesn't work:

$ cat makefile
BASEDIR = ${HOME}/Downloads
MYDIR = ${BASEDIR}/ddd
all:
    for f in $(shell ls ${MYDIR}); do echo ${f}; done

$ make
for f in d.txt m.txt; do echo ; done

Answer 1

Maybe you can do it purely Makefile way?

MYDIR = .
list: $(MYDIR)/*
        @echo $^

You can still run command from Makefile like this

MYDIR = .
list: $(MYDIR)/*
        for file in $^ ; do \
                echo "Hello" $${file} ; \
        done

If I were you, I'd rather not mix Makefile and bash loops based on $(shell ...). I'd rather pass dir name to some script and run loop there - inside script.