I am new to this type of programming, so sorry if my question is trivial. What I am trying to do is to cause a segmentation fault in my program and instead of exiting the program, I want to handle the signal and continue execution after segmentation fault. I wrote a code that seem to be working, I just want to make sure that this is the way to do this. So here is my code.
void myhandle(int mysignal, siginfo_t *si, void* arg)
{
printf("Signal is %d\n",mysignal);
ucontext_t *context = (ucontext_t *)arg;
context->uc_mcontext.gregs[REG_RIP]++;
}
int main(int argc, char *argv[])
{
struct sigaction action;
action.sa_handler=myhandle;
sigaction(11,&action,NULL);
printf("Before segfault\n");
int *a=NULL;
int b=*a;
printf("I am still alive\n");
return 0;
}
Can someone explain to me why the printf inside myhandle runs twice ? Also is this code ok ?
Thank you.
By this example i have modified your code at below way and now it works as you wanted.
#include<stdio.h>
#define __USE_GNU
#include<signal.h>
#include<ucontext.h>
void myhandle(int mysignal, siginfo_t *si, void* arg)
{
printf("Signal is %d\n",mysignal);
ucontext_t *context = (ucontext_t *)arg;
context->uc_mcontext.gregs[REG_RIP] = context->uc_mcontext.gregs[REG_RIP] + 0x04 ;
}
int main(int argc, char *argv[])
{
struct sigaction action;
action.sa_sigaction = &myhandle;
action.sa_flags = SA_SIGINFO;
sigaction(11,&action,NULL);
printf("Before segfault\n");
int *a=NULL;
int b;
b =*a;
printf("I am still alive\n");
return 0;
}
Output:
jeegar@jeegar:~/stackoverflow$ gcc test1.c
jeegar@jeegar:~/stackoverflow$ ./a.out
Before segfault
Signal is 11
I am still alive
On further question form OP in commentes. To runtime remove this handler for this signel
void myhandle(int mysignal, siginfo_t *si, void* arg)
{
printf("Signal is %d\n",mysignal);
if(flag == 0) {
// Disable the handler
action.sa_sigaction = SIG_DFL;
sigaction(11,&action,NULL);
}
if(flag) {
ucontext_t *context = (ucontext_t *)arg;
context->uc_mcontext.gregs[REG_RIP] = context- >uc_mcontext.gregs[REG_RIP] + 0x04 ;
}
}
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