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I need a page with checkboxes and visible div if at minimum 1 is checked.
Here I got page that if i check checkbox, the div will show. It's okay and works correctly.
When I check 3 checkboxes and uncheck 1, the div is missing, when i check some box again, the div will show - it isn't correct.
How do I need modify the script to show all time the div, if at minimum 1 checkbox is checked, without this "jumping"?
<html>
<head>
<title>CB Hide/Show</title>
<script type="text/javascript">
<!--
function showMe (it, box) {
var vis = (box.checked) ? "block" : "none";
document.getElementById(it).style.display = vis;
}
//-->
</script>
</head>
<body>
<h3 align="center"> This JavaScript shows how to hide divisions </h3>
<div id="div1" style="display:none">
<table border=1 id="t1">
<tr>
<td>i am here!</td>
</tr>
</table>
</div>
<form>
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1', this)">Show Hide Checkbox
</form>
</body>
</html>
219
Every time the checkbox is clicked, the handleClick function is invoked. In the function, we check if the checkbox is checked and if it is, we set the display property of the div element to block to show it. If you uncheck the checkbox, the div's display property is set to none and the element is hidden.
To show or hide the field, we are applying CSS through jQuery css() method. We are passing CSS display property. To hide the field, we set the display property to none and to show it we set the display property block. So you have seen how to show or hide input field depending upon a checkbox field.
We hide the divs by adding a CSS class called hidden to the outer div called . text_container . This will trigger CSS to hide the inner div.
change the input boxes like
<input type="checkbox" name="c1" onclick="showMe('div1')">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1')">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1')">Show Hide Checkbox
<input type="checkbox" name="c1" onclick="showMe('div1')">Show Hide Checkbox
and js code as
function showMe (box) {
var chboxs = document.getElementsByName("c1");
var vis = "none";
for(var i=0;i<chboxs.length;i++) {
if(chboxs[i].checked){
vis = "block";
break;
}
}
document.getElementById(box).style.display = vis;
}
here is a demo fiddle
115
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