Show / Hide contents base on radio button selection

Question

I am trying to toggle a content DIV base on the selection of radio buttons.

HTML for radio button.

<div class="row-fluid">
    <label class="radio">
      <input type="radio" name="account" id="yes" value="yes" checked>
      Yes, I have an existing account
    </label>
    <label class="radio">
      <input type="radio" name="account" id="no" value="no">
      No, I don't have an account
    </label>
</div>

Content DIV

<div id="account_contents">
    <p>This is account contents.......</p>  
</div>

This is how I tried it in jquery.

$('#no').bind('change',function(){
  $('#account_contents').fadeToggle(!$(this).is(':checked'));
  $('#account_contents').find("input").val("");
  $('#account_contents').find('select option:first').prop('selected',true);
});

But it doesn't work for me correctly. Here I want to show this content DIV only if user don't have an account.

Can anybody tell me how to fix this problem?

Answer 1

seems you need .on('change') for radio buttons not just for one of them

$('input[type="radio"][name="account"]').on('change',function(){
  var ThisIt = $(this);
  if(ThisIt.val() == "yes"){
       // when user select yes
       $('#account_contents').fadeOut();
  }else{
       // when user select no
       $('#account_contents').fadeIn();
       $('#account_contents').find("input").val("");
       $('#account_contents').find('select option:first').prop('selected',true);
  }
});

Working Example

Answer 2

  $(document).ready(function(){
            $('.radio input[type="radio"]').on("click", function(){
            if($('.radio input[type="radio"]:checked').val() === "yes"){
                $("#account_contents").slideDown("slow");
            }else{
                $("#account_contents").slideUp("slow");
            }
          });
     });