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my_string = 'Here's the #: 49848! - but will dashes, commas & stars (*) show?'
puts src.gsub(/\d|\W/, "")
i.e. can I remove the or ("|").
Here's how I got here, can I get shorter?
src = "Here's the #: 49848! - but will dashes, commas & stars (*) show?"
puts "A) - " + src
puts "B) - " + src.gsub(/\d\s?/, "")
puts "C) - " + src.gsub(/\W\s?/, "")
puts "D) - " + src.gsub(/\d|\W\s?/, "")
puts "E) - " + src.gsub(/\d|\W/, "")
puts "F) - " + src
A) - Here's the #: 49848! - but will dashes, commas & stars (*) show?
B) - Here's the #: ! - but will dashes, commas & stars (*) show?
C) - Heresthe49848butwilldashescommasstarsshow
D) - Heresthebutwilldashescommasstarsshow
E) - Heresthebutwilldashescommasstarsshow
F) - Here's the #: 49848! - but will dashes, commas & stars (*) show?
n.d. D) and E) are what I want for output. Just characters.
356
We will remove non-alphanumeric characters by using str_replace_all() method. [^[:alnum:]] is the parameter that removes the non-alphanumeric characters.
To remove a character in an R data frame column, we can use gsub function which will replace the character with blank. For example, if we have a data frame called df that contains a character column say x which has a character ID in each value then it can be removed by using the command gsub("ID","",as.
The “sub” in “gsub” stands for “substitute”, and the “g” stands for “global”. Here is an example string: str = "white chocolate" Let's say that we want to replace the word “white” with the word “dark”. Here's how: str.gsub("white", "dark")
Regular expressions (shortened to regex) are used to operate on patterns found in strings. They can find, replace, or remove certain parts of strings depending on what you tell them to do.
my_string = "Here's the #: 49848! - but will dashes, commas & stars (*) show?"
p my_string.delete('^a-zA-Z')
#=>"Heresthebutwilldashescommasstarsshow"
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