Short command to find total size of files matching a wild card

Question

I could envision a simple shell script that would accomplish what I want by just iterating through a list of files in a directory and summing the individual size but was wondering if there was already a more concise way to do that.

something like

ls -lh *.jpg 

that gives me the total size of just all the jpg files in the directory

Answer 1

Try du to summarize disk usage:

du -csh *.jpg 

Output (for example):

8.0K sane-logo.jpg 16K sane-umax-advanced.jpg 28K sane-umax-histogram.jpg 24K sane-umax.jpg 16K sane-umax-standard.jpg 4.0K sane-umax-text2.jpg 4.0K sane-umax-text4.jpg 4.0K sane-umax-text.jpg 104K total 

du does not summarize the size of the files but summarizes the size of the used blocks in the file system. If a file has a size of 13K and the file system uses a block size of 4K, then 16K is shown for this file.

Answer 2

You can use this function :

dir () { ls -FaGl "${@}" | awk '{ last_size += $4; print }; END { print last_size }'; } 

also you can use this command this is shorter and give you better result!

find YOUR_PATH -type f -name '*.jpg' -exec du -ch {} +