Shell script to capture Process ID and kill it if exist [duplicate]

Question

I tried this code and it is not working

#!/bin/sh  #Find the Process ID for syncapp running instance  PID=`ps -ef | grep syncapp 'awk {print $2}'`  if [[ -z "$PID" ]] then Kill -9 PID fi 

It is showing a error near awk.

Any suggestions please.

Answer 1

Actually the easiest way to do that would be to pass kill arguments like below:

ps -ef | grep your_process_name | grep -v grep | awk '{print $2}' | xargs kill 

Hope it helps.

Answer 2

This works good for me.

 PID=`ps -eaf | grep syncapp | grep -v grep | awk '{print $2}'` if [[ "" !=  "$PID" ]]; then   echo "killing $PID"   kill -9 $PID fi