Shell Script call a function with a variable?

Question

Hi I'm creating a shell script.

and an example code looks like

#!/bin/bash

test_func(){
{
  echo "It works!"
}

funcion_name = "test_func"

I want to somehow be able to call test_func() using the variable "function_name"

I know that's possible in php using call_user_func($function_name) or by sying $function_name()

is this also possible in the shell scripting?

Huge appreciation for the help! :)

Answer 1

You want the bash built-in eval. From man bash:

eval [arg ...] The args are read and concatenated together into a single command. This command is then read and executed by the shell, and its exit status is returned as the value of eval. If there are no args, or only null arguments, eval returns 0.

You can also accomplish it with simple variable substitution, as in

#!/bin/bash

test_func() {
  echo "It works!"
}

function_name="test_func"

$function_name