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Shape Detection in python using OpenCV

I'm working on a project in which I use OpenCV to detect shapes and their colors.

There are 5 colors (red, green, yellow, blue and white) and 4 shapes (rectangle, star, circle and heart). I've been able to reliably discern the colors and I can detect the shapes when the image used is a drawn image like this using this code. Note, the image is for demonstration only, the range values in my code are not for these colors.

import cv2
import numpy as np
class Shape():

    def __init__(self, color, shape, x, y, approx):
        self.color = color
        self.shape = shape
        self.x = x
        self.y = y
        self.approx = approx
def closing(mask):
kernel = np.ones((7,7),np.uint8) 
closing = cv2.morphologyEx(mask, cv2.MORPH_CLOSE, kernel)
return closing

def opening(mask):
    kernel = np.ones((6,6),np.uint8)
    opening = cv2.morphologyEx(mask, cv2.MORPH_OPEN, kernel)
    return opening

#Define Red
lower_red = np.array([0, 90, 60], dtype=np.uint8)
upper_red = np.array([10, 255, 255], dtype=np.uint8)
red = [lower_red, upper_red, 'red']

#Define Green
lower_green = np.array([60, 55, 0], dtype=np.uint8)
upper_green = np.array([100, 255, 120], dtype=np.uint8)
green = [lower_green, upper_green, 'green']

#Define Blue
lower_blue = np.array([90, 20, 60], dtype=np.uint8)
upper_blue = np.array([130, 255, 180], dtype=np.uint8)
blue = [lower_blue, upper_blue, 'blue']

#Define Yellow
lower_yellow = np.array([5, 110, 200], dtype=np.uint8)
upper_yellow = np.array([50, 255, 255], dtype=np.uint8)
yellow = [lower_yellow, upper_yellow, 'yellow']

#Define White
lower_white = np.array([0, 90, 60], dtype=np.uint8)
upper_white = np.array([10, 255, 255], dtype=np.uint8)
white = [lower_white, upper_white ,'white']

colors = [red, green, blue, yellow, white]

def detect_shapes(image_location):
    #Open image
    img = cv2.imread(image_location)

    #Convert to hsv
    hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)

    #Shape list
    shapes = []

    #Lay over masks and detect shapes
    for color in colors:
        mask = cv2.inRange(hsv, color[0], color[1])
        mask = closing(mask)
        mask = opening(mask)
        contours, h = cv2.findContours(mask, 1, cv2.CHAIN_APPROX_SIMPLE)
        contours.sort(key = len)
        for contour in contours[-3:]:
            #Amount of edges
            approx = cv2.approxPolyDP(contour, 0.01*cv2.arcLength(contour, True), True)
            #Center locations
            M = cv2.moments(contour)
            if M['m00'] == 0.0:
                continue
            centroid_x = int(M['m10']/M['m00'])
            centroid_y = int(M['m01']/M['m00'])

            if len(approx) == 4:
                shape_name = 'rectangle'
            elif len(approx) == 10:
                shape_name = 'star'
            elif len(approx) >= 11:
                shape_name = 'oval'
            else:
                shape_name ='undefined'

            shape = Shape(color[2], shape_name, centroid_x, centroid_y, len(approx))
            shapes.append(shape)

    return shapes

This is largely based off the answers on this question.

However, when I try to detect the shapes on an actual photo, I cannot reliably use this. The amount of edges I get varies wildly. This is an example of a photo I need to recognize the shapes on. I'm guessing this happens because of small imperfections on the edges of the shapes, but I can't figure out how I would approximate those edges with straight lines, or how I would reliably recognize circles. What would I need to change in the code to do this? Intensive googling hasn't given me an answer yet but that might be because I'm not using the correct terminology in the searches...

Also, if this question is not formatted correctly, let me know!

like image 293
Habba Avatar asked Feb 25 '14 19:02

Habba


People also ask

What function is used to detect polygons OpenCV?

Contours – convex contours and the Douglas-Peucker algorithm The first facility OpenCV offers to calculate the approximate bounding polygon of a shape is cv2. approxPolyDP. This function takes three parameters: A contour.

What is shape in OpenCV?

The dimensions of a given image like the height of the image, width of the image and number of channels in the image are called the shape of the image. The shape of the image is stored in numpy. ndarray.

How do I find the shape of an image?

We can find shapes present in an image using the findContours() and approxPolyDP() function of OpenCV. We can detect shapes depending on the number of corners it has. For example, a triangle has 3 corners, a square has 4 corners, and a pentagon has 5 corners.


1 Answers

Here is the code I proceed with your image, the code will do

  1. Blur the source
  2. Canny Edge detection.
  3. Find contour.
  4. approxPolyDP for the contour.
  5. Check total size of approxPolyDP points.

Code:

   Mat src=imread("src.jpg",1);
   Mat thr,gray;
   blur(src,src,Size(3,3));
   cvtColor(src,gray,CV_BGR2GRAY);
   Canny(gray,thr,50, 190, 3, false );
   vector<vector<Point> > contours;
   vector<Vec4i> hierarchy;
   findContours( thr.clone(),contours,hierarchy,CV_RETR_EXTERNAL,CV_CHAIN_APPROX_SIMPLE,Point(0,0));

   vector<vector<Point> > contours_poly(contours.size());
   vector<Rect> boundRect( contours.size() );
   vector<Point2f>center( contours.size() );
   vector<float>radius( contours.size() );
   vector<vector<Point> >hull( contours.size() );
   for( int i = 0; i < contours.size(); i++ )
    {
    approxPolyDP( Mat(contours[i]), contours_poly[i], 10, true );
    boundRect[i] = boundingRect( Mat(contours_poly[i]) );
    minEnclosingCircle( (Mat)contours_poly[i], center[i], radius[i] );
    convexHull( Mat(contours[i]), hull[i], false );

    if( contours_poly[i].size()>15) // Check for corner
       drawContours( src, contours_poly, i, Scalar(0,255,0), 2, 8, vector<Vec4i>(), 0, Point() ); // True object
    else
       drawContours( src, contours_poly, i, Scalar(0,0,255), 2, 8, vector<Vec4i>(), 0, Point() ); // false object
      //drawContours( src, hull, i, Scalar(0,0,255), 2, 8, vector<Vec4i>(), 0, Point() );
      // rectangle( src, boundRect[i].tl(), boundRect[i].br(), Scalar(0,255,0), 2, 8, 0 );
       //circle( src, center[i], (int)radius[i], Scalar(0,0,255), 2, 8, 0 );
    }
   imshow("src",src);
   imshow("Canny",thr);
   waitKey();

enter image description hereenter image description here

like image 75
Haris Avatar answered Nov 14 '22 21:11

Haris