Setting nth bit of unsigned int [duplicate]

Question

Given a unsigned int x, I want to set the nth bit to y, and y can be either 0 or 1. Is it possible to create an expression using bitwise operators to do this while avoiding the use of any conditional statements? Thanks.

Answer 1

x = (x & (~(1 << n))) | (y << n)

Quite simple. (First, clear the nth bit, and set nth bit to 1 if y is 1.)

Answer 2

x ^= (-y ^ x) & (1 << n);