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Infinite loop while adding two integers using bitwise operations?

I am trying to solve a problem, using python code, which requires me to add two integers without the use of '+' or '-' operators. I have the following code which works perfectly for two positive numbers:

def getSum(self, a, b):

    while (a & b):
        x = a & b
        y = a ^ b
        a = x << 1
        b = y

    return a ^ b

This piece of code works perfectly if the input is two positive integers or two negative integers but it fails when one number is positive and other is negative. It goes into an infinite loop. Any idea as to why this might be happening?

EDIT: Here is the link discussing the code fix for this.

like image 366
Mr Matrix Avatar asked Aug 24 '16 02:08

Mr Matrix


1 Answers

Python 3 has arbitrary-precision integers ("bignums"). This means that anytime x is negative, x << 1 will make x a negative number with twice the magnitude. Zeros shifting in from the right will just push the number larger and larger.

In two's complement, positive numbers have a 0 in the highest bit and negative numbers have a 1 in the highest bit. That means that, when only one of a and b is negative, the top bits of a and b will differ. Therefore, x will be positive (1 & 0 = 0) and y will be negative (1 ^ 0 = 1). Thus the new a will be positive (x<<1) and the new b will be negative (y).

Now: arbitrary-precision negative integers actually have an infinite number of leading 1 bits, at least mathematicallly. So a is a larger and larger positive number, expanding by 2 each iteration. b keeps getting more and more leading 1 bits added to be able to carry out the bitwise & and ^ with a. Thus whatever bits of a are turned on line up with one of the added 1 bits of b, so a & b is always true, so the loop runs forever.

like image 188
cxw Avatar answered Oct 15 '22 01:10

cxw