Set variable to result of "Find" in batch-file

Question

I would like to set a variable based on the number of lines in a file that contain a give string.

Something like:

set isComplete = 0
%isComplete% = find /c /i "Transfer Complete" "C:\ftp.LOG"
IF %isComplete% > 0 ECHO "Success" ELSE ECHO "Failure"

Or:

set isComplete = 0
find /c /i "Transfer Complete" "C:\ftp.LOG" | %isComplete%
IF %isComplete% > 0 ECHO "Success" ELSE ECHO "Failure"

Neither of those options work, obviously.

Thanks.

Answer 1

from the command line

for /f "tokens=3" %f in ('find /c /i "Transfer Complete" "C:\ftp.LOG"') do set isComplete=%f 

from the batch script

for /f "tokens=3" %%f in ('find /c /i "Transfer Complete" "C:\ftp.LOG"') do set isComplete=%%f 

Answer 2

You don't need to use the for command; find will set the ERRORLEVEL to one of these values, based on the result:

• 0, At least one match was found.
• 1, no matches were found.
• 2 or more, an error occurred.

Since it looks like you just want to see if the transfer completed, and not the total count of times the string appears, you can do something like this:

@echo OFF

@find /c /i "Transfer Complete" "C:\test path\ftp.LOG" > NUL
if %ERRORLEVEL% EQU 0 (
    @echo Success
) else (
    @echo Failure
)