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<span class="selector">References (27)</span></a></li>
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In this I need to find and click About link using Selenium api but I was unable to do it.
what I did is
wait.until(new ExpectedCondition<Boolean>() {
public Boolean apply(WebDriver webDriver) {
System.out.println("Searching ...");
String s = driver.findElement(By.cssSelector("#ContentPrimary ul li[4] span.selector")).getText();
System.out.println(s);
if (Pattern.compile(Pattern.quote("About"), Pattern.CASE_INSENSITIVE).matcher(s).find()) {
return true;
} else {
return false;
}
}
});
driver.findElement(By.linkText("About")).click();
but its not working
A linkText is used to identify the hyperlinks on a web page. It can be determined with the help of an anchor tag (<a>). In order to create the hyperlinks on a web page, you can use anchor tags followed by the linkText.
We can click a button with Selenium webdriver in Python using the click method. First, we have to identify the button to be clicked with the help of any locators like id, name, class, xpath, tagname or css. Then we have to apply the click method on it. A button in html code is represented by button tagname.
We can click on a link using Selenium webdriver in Python. A link is represented by the anchor tag. A link can be identified with the help of the locators like - link text and partial link text. We can use the link text attribute for an element for its identification and utilize the method find_element_by_link_text.
In my experience the Selenium API has many flaws in that way. They can mostly only be overcome by reformulating your selectors. For example you could try using a XPath selector to get your element:
driver.findElement(By.xpath("//a[contains(.,'About')]")).click();
Also, if you are trying to use the Internet Explorer it might help not to click the element, but instead to simulate pushing the Enter button. So assumung the Element is found, you could try this:
driver.findElement(By.linkText("About")).sendKeys(Keys.ENTER);
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