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excuse the title, i couldn't come up with something short and to the point...
I've got a table 'updates' with the three columns, text, typeid, created - text is a text field, typeid is a foreign key from a 'type' table and created is a timestamp. A user is entering an update and select the 'type' it corresponds too.
There's a corresponding 'type' table with columns 'id' and 'name'.
I'm trying to end up with a result set with as many rows as is in the 'type' table and the latest value from updates.text for the particular row in types. So if i've got 3 types, 3 rows would be returned, one row for each type and the most recent updates.text value for the type in question.
Any ideas?
thanks,
John.
356
The following is the syntax to get the last 10 records from the table. Here, we have used LIMIT clause. SELECT * FROM ( SELECT * FROM yourTableName ORDER BY id DESC LIMIT 10 )Var1 ORDER BY id ASC; Let us now implement the above query.
The DISTINCT clause can be applied to one or more columns in the select list of the SELECT statement.
Select * from any table will fetch and display all the column in that table, while Select 1 from any table will display one row with 1 without any column name.
The DISTINCT clause filters out FULL DUPLICATE ROWS. It goes right after the SELECT keyword, since it applies to the entire row, not single columns. You cannot use it in between columns.
select u.text, u.typeid, u.created, t.name
from (
select typeid, max(created) as MaxCreated
from updates
group by typeid
) mu
inner join updates u on mu.typeid = u.typeid and mu.MaxCreated = u.Created
left outer join type t on u.typeid = t.typeid
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