I have been looking for a way to get multiple columns but group by only one in SQL and I found some info. However I can not came up with a way to do it in linq.
I have the following toy example table:
| Id | Message | GroupId | Date |
|-------------------------------|
| 1 | Hello | 1 | 1:00 |
| 2 | Hello | 1 | 1:01 |
| 3 | Hey | 2 | 2:00 |
| 4 | Dude | 3 | 3:00 |
| 5 | Dude | 3 | 3:01 |
And I would like to recover all columns for the rows that have a distinct GroupId
as follows (with a 'Date' desc order):
| Id | Message | GroupId | Date |
|-------------------------------|
| 1 | Hello | 1 | 1:00 |
| 3 | Hey | 2 | 2:00 |
| 4 | Dude | 3 | 3:00 |
I do not really care about which row is picked from the grouped ones (first, second...) as long as is the only one given that group Id.
I have came out with the following code so far but it does not do what is supposed to:
List<XXX> messages = <MyRep>.Get(<MyWhere>)
.GroupBy(x => x.GroupId)
.Select(grp => grp.OrderBy(x => x.Date))
.OrderBy(y => y.First().Date)
.SelectMany(y => y).ToList();
This will give you one item per group:
List<dynamic> data = new List<dynamic>
{
new {ID = 1, Message = "Hello", GroupId = 1, Date = DateTime.Now},
new {ID = 2, Message = "Hello", GroupId = 1, Date = DateTime.Now},
new {ID = 3, Message = "Hey", GroupId = 2, Date = DateTime.Now},
new {ID = 4, Message = "Dude", GroupId = 3, Date = DateTime.Now},
new {ID = 5, Message = "Dude", GroupId = 3, Date = DateTime.Now},
};
var result = data.GroupBy(item => item.GroupId)
.Select(grouping => grouping.FirstOrDefault())
.OrderByDescending(item => item.Date)
.ToList();
//Or you can also do like this:
var result = data.GroupBy(item => item.GroupId)
.SelectMany(grouping => grouping.Take(1))
.OrderByDescending(item => item.Date)
.ToList();
If you want to control OrderBy
then:
var result = data.GroupBy(item => item.GroupId)
.SelectMany(grouping => grouping.OrderBy(item => item.Date).Take(1))
.OrderByDescending(item => item.Date)
.ToList();
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