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I'd like to substitute some text with an incremental value. Considering file xx:
<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
and sed command:
for n in seq 3;do sed -e 's/<RecordID>\d/<RecordID>'`echo $n`'/' xx; done
the echo $n command does not get incremented.
Tryed also:
n=1; sed -e 's/<RecordID>/<RecordID>'`echo $n ;let n=$n+1`'/g' xx
but with no success.
Considering only sed (no awk or perl) how can I have the RecordID field incremented as in:
<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
<RecordID>2</RecordID>
<outro>dfdfd</outro>
<RecordID>3</RecordID>
<outro>dfdfd</outro>
370
To increment one number you just add 1 to last digit, replacing it by the following digit. There is one exception: when the digit is a nine the previous digits must be also incremented until you don't have a nine.
The I flag allows to match a pattern case insensitively. Usually i is used for such purposes, grep -i for example. But i is a command (discussed in append, change, insert chapter) in sed , so /REGEXP/i cannot be used. The substitute command does allow both i and I to be used, but I is recommended for consistency.
while read line; do n=$((++n)) && echo $line|sed -e 's/[0-9]/'$(($n))'/' ; done < patt
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