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Scipy optimize fmin ValueError: setting an array element with a sequence

When using scipy.optimize's fmin I'm getting an error I don't understand:

ValueError: setting an array element with a sequence.

Here's a simple squared error example to demonstrate:

import numpy as np
from scipy.optimize import fmin

def cost_function(theta, X, y):    
    m = X.shape[0]
    error = X.dot(theta) - y 
    J = 1/(2*m) * error.T.dot(error)  
    return J

X = np.array([[1., 1.],
              [1., 2.],
              [1., 3.],
              [1., 4.]])

y = np.array([[2],[4],[6],[8]])   
initial_theta = np.ones((X.shape[1], 1)) * 0.01

# test cost_function
print cost_function(initial_theta, X, y)
# [[ 14.800675]] seems okay...

# but then error here...   
theta = fmin(cost_function, initial_theta, args=(X, y))

#Traceback (most recent call last):
#  File "C:\Users\me\test.py", line 21, in <module>
#    theta = fmin(cost_function, initial_theta, args=(X, y))
#  File "C:\Python27\lib\site-packages\scipy\optimize\optimize.py", line 278, in fmin
#    fsim[0] = func(x0)
#ValueError: setting an array element with a sequence.

I'd be grateful for any help to explain where I'm going wrong.

like image 225
Kim Avatar asked Mar 20 '12 00:03

Kim


2 Answers

The reason is that the starting point (initial_theta) you gave to fmin is not a 1D array but a 2D array. So on a second iteration fmin passes a 1D array (that's how it supposed to work) and the result becomes non-scalar.

So you should refactor your cost function to accept 1d arrays as a first argument.

The simplest change is to make the code working is to flatten the initial_theta before passing to fmin and reshape theta inside cost_function to (X.shape[1],1) if you like.

like image 185
sega_sai Avatar answered Oct 04 '22 17:10

sega_sai


cost_function should return a scalar, but your return value J is an array of some kind.

like image 20
YXD Avatar answered Oct 04 '22 18:10

YXD