I want to be able to refer to a list that contains subtypes and pull elements from that list and have them implicitly casted. Example follows:
scala> sealed trait Person { def id: String }
defined trait Person
scala> case class Employee(id: String, name: String) extends Person
defined class Employee
scala> case class Student(id: String, name: String, age: Int) extends Person
defined class Student
scala> val x: List[Person] = List(Employee("1", "Jon"), Student("2", "Jack", 23))
x: List[Person] = List(Employee(1,Jon), Student(2,Jack,23))
scala> x(0).name
<console>:14: error: value name is not a member of Person
x(0).name
^
I know that x(0).asInstanceOf[Employee].name
but I was hoping there was a more elegant way with types. Thanks in advance.
The best way is to use pattern matching. Because you are using a sealed trait the match will be exhaustive which is nice.
x(0) match {
case Employee(id, name) => ...
case Student(id, name, age) => ...
}
Well, if you want the employees, you could always use a collect
:
val employees = x collect { case employee: Employee => employee }
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