I'm trying to implement type-level multiplication in Rust.
Addition is already working, but I got issues with a "temporary" type variable.
The code:
use std::marker::PhantomData;
//Trait for the type level naturals
trait Nat {}
impl Nat for Zero {}
impl<T: Nat> Nat for Succ<T> {}
//Zero and successor types
struct Zero;
struct Succ<T: Nat>(PhantomData<T>);
//Type level addition
trait Add<B,C>
where Self: Nat,
B: Nat,
C: Nat
{}
impl<B: Nat> Add<B,B> for Zero {}
impl<A: Nat,B: Nat,C: Nat> Add<B,C> for Succ<A>
where A: Add<Succ<B>,C>
{}
fn add<A: Nat, B: Nat, C: Nat>(
a: PhantomData<A>,
b: PhantomData<B>)
-> PhantomData<C>
where A: Add<B,C> { PhantomData }
//Type level multiplication
trait Mult<B,C>
where Self: Nat,
B: Nat,
C: Nat,
{}
impl<B: Nat> Mult<B,Zero> for Zero {}
//ERROR HERE: "unconstrained type parameter 'C'"
//impl<A: Nat, B: Nat,C: Nat, D: Nat> Mult<B,D> for Succ<A>
// where A: Mult<B,C>,
// B: Add<C,D>
// {}
fn main() {
let x: PhantomData<Succ<Succ<Zero>>> = PhantomData;
let y: PhantomData<Succ<Zero>> = PhantomData;
//uncomment ': i32' in the next line to see infered type
let z /*: i32*/ = add(x,y);
}
The posted code compiles just fine and addition works. If I uncomment the ERROR HERE section I get the following error message:
error[E0207]: the type parameter `C` is not constrained by the impl trait, self type, or predicates
--> src/main.rs:40:21
|
40 | impl<A: Nat, B: Nat,C: Nat, D: Nat> Mult<B,D> for Succ<A>
| ^ unconstrained type parameter
error: aborting due to previous error
error: Could not compile `4_18_generics`.
To learn more, run the command again with --verbose.
Is there a way to use such "temporary/intermediate" type parameters?
Is multiplication possible in any other way (I am currently not thinking of)?
Is it generally not possible?
Will it be possible in a future version of the language?
I think you are misusing generics, and that is the root of your issue.
Generics in Rust have inputs and outputs:
<>
The intuition is that for a given set of inputs, a single type is selected for each output.
In your case, we have to rework the traits for that:
trait Add<Rhs: Nat>: Nat {
type Result: Nat;
}
The definition of the trait says:
Add
requires that Self
be Nat
Add
is implemented for a right-hand side argument which must be Nat
Add
has a Result
type, which must be Nat
Now we can implement it:
impl<T: Nat> Add<T> for Zero {
type Result = T;
}
impl<A: Nat, B: Nat> Add<B> for Succ<A>
where A: Add<Succ<B>>
{
type Result = < A as Add<Succ<B>> >::Result;
}
Note that functions are completely unnecessary, the result of "A + B" is:
<A as Add<B>>::Result
Now, on to multiplication:
trait Mul<Rhs: Nat>: Nat {
type Result: Nat;
}
impl<T: Nat> Mul<T> for Zero {
type Result = Zero;
}
// The first attempt does not work, but I'm keeping it here as
// it is good for learning purpose.
//
// impl<A: Nat, B: Nat> Mul<B> for Succ<A>
// where A: Mul<B> + Add< <A as Mul<B>>::Result >
// {
// type Result = <A as Add< <A as Mul<B>>::Result >>::Result;
// }
//
// Think:
// 1. Why exactly does it not work?
// 2. What exactly is going on here?
// 3. How would you multiply numbers in terms of addition?
// 4. m * n = m + m + m ... (n times)? Or: n + n + .. (m times)?
//
// Answering these questions will help learning the intricacies of
// Rust's traits/type-system and how they work.
impl<A: Nat, B: Nat> Mul<B> for Succ<A>
where
A: Mul<B>,
B: Add<<A as Mul<B>>::Result>,
{
type Result = <B as Add<<A as Mul<B>>::Result>>::Result;
}
And this now compiles:
fn main() {
type One = Succ<Zero>;
type Two = <One as Add<One>>::Result;
type Four = <Two as Mul<Two>>::Result;
}
Note that such Peano arithmetic has fairly annoying limitations though, notably in the depth of recursion. Your addition is O(N), your multiplication is O(N^2), ...
If you are interested in more efficient representations and computations, I advise you to check the typenum crate which is the state of the art.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With