Running module from ipython interpreter instead of command line

Question

I'm working on a package, and I have a structure like:

 mypackage/
    __init__.py
    __main__.py
    someotherstuff.py
    test/
        __init__.py
        testsomeotherstuff.py

I've set it up so that the main.py function runs some unit tests, and executing python mypackage from the command-line works fine. However often I want to debut using ipython, but from the interpreter, run mypackage gives the error ERROR: File 'mypackage.py' not found. I can run it manually by doing run mypackage/__main__.py but somehow this seems wrong. Is there something else I should have done to set this up correctly?

Answer 1

Running a package as a program was introduced in Python 2.5. I don't think IPython has a native feature for this, but starting with version 2.7, the Python standard library has, namely the runpy.run_module() function. Note that this behaves slightly different than IPython's %run, since it will return the global dictionary of the module instead of directly importing it into the interpreter scope.