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Run two async tasks in parallel and collect results in .NET 4.5

People also ask

Do async tasks run in parallel?

There is no parallelism here, as the “async Task” does not automatically make something run in in parallel. This will spawn 2 threads, run them simultaneously, and return when both threads are done. This will create a list of Tasks to be run at the same time.

How can I run two functions at the same time in C#?

In C#, the Thread class represents a thread. The constructor of the Thread class takes a method that will be executed when a thread starts. In the code listed below, I create two threads and call the Start method to start executing them simultaneously.

Is async await parallel C#?

With TPL we can implement Parallel Programming in C# . NET very easy. Async and Await keywords were introduced in C# 5.0 by Microsoft. When you use the “Async” keyword, you can write code the same way you wrote synchronous code.


async Task<int> LongTask1() { 
  ...
  return 0; 
}

async Task<int> LongTask2() { 
  ...
  return 1; 
}

...
{
   Task<int> t1 = LongTask1();
   Task<int> t2 = LongTask2();
   await Task.WhenAll(t1,t2);
   //now we have t1.Result and t2.Result
}

You should use Task.Delay instead of Sleep for async programming and then use Task.WhenAll to combine the task results. The tasks would run in parallel.

public class Program
    {
        static void Main(string[] args)
        {
            Go();
        }
        public static void Go()
        {
            GoAsync();
            Console.ReadLine();
        }
        public static async void GoAsync()
        {

            Console.WriteLine("Starting");

            var task1 = Sleep(5000);
            var task2 = Sleep(3000);

            int[] result = await Task.WhenAll(task1, task2);

            Console.WriteLine("Slept for a total of " + result.Sum() + " ms");

        }

        private async static Task<int> Sleep(int ms)
        {
            Console.WriteLine("Sleeping for {0} at {1}", ms, Environment.TickCount);
            await Task.Delay(ms);
            Console.WriteLine("Sleeping for {0} finished at {1}", ms, Environment.TickCount);
            return ms;
        }
    }

While your Sleep method is async, Thread.Sleep is not. The whole idea of async is to reuse a single thread, not to start multiple threads. Because you've blocked using a synchronous call to Thread.Sleep, it's not going to work.

I'm assuming that Thread.Sleep is a simplification of what you actually want to do. Can your actual implementation be coded as async methods?

If you do need to run multiple synchronous blocking calls, look elsewhere I think!


To answer this point:

I want Sleep to be an async method so it can await other methods

you can maybe rewrite the Sleep function like this:

private static async Task<int> Sleep(int ms)
{
    Console.WriteLine("Sleeping for " + ms);
    var task = Task.Run(() => Thread.Sleep(ms));
    await task;
    Console.WriteLine("Sleeping for " + ms + "END");
    return ms;
}

static void Main(string[] args)
{
    Console.WriteLine("Starting");

    var task1 = Sleep(2000);
    var task2 = Sleep(1000);

    int totalSlept = task1.Result +task2.Result;

    Console.WriteLine("Slept for " + totalSlept + " ms");
    Console.ReadKey();
}

running this code will output :

Starting
Sleeping for 2000
Sleeping for 1000
*(one second later)*
Sleeping for 1000END
*(one second later)*
Sleeping for 2000END
Slept for 3000 ms

It's weekend now!

    public async void Go()
    {
        Console.WriteLine("Start fosterage...");

        var t1 = Sleep(5000, "Kevin");
        var t2 = Sleep(3000, "Jerry");
        var result = await Task.WhenAll(t1, t2);

        Console.WriteLine($"My precious spare time last for only {result.Max()}ms");
        Console.WriteLine("Press any key and take same beer...");
        Console.ReadKey();
    }

    private static async Task<int> Sleep(int ms, string name)
    {
            Console.WriteLine($"{name} going to sleep for {ms}ms :)");
            await Task.Delay(ms);
            Console.WriteLine("${name} waked up after {ms}ms :(";
            return ms;
    }