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This is Ruby 1.8.7 but should be same as for 1.9.x
I am trying to split a string for example:
a = "foo.bar.size.split('.').last" # trying to split into ["foo", "bar","split('.')","last"] Basically splitting it in commands it represents, I am trying to do it with Regexp but not sure how, idea was to use regexp
a.split(/[a-z\(\)](\.)[a-z\(\)]/) Here trying to use group (\.) to split it with but this seems not to be good approach.
603
split is a String class method in Ruby which is used to split the given string into an array of substrings based on a pattern specified. Here the pattern can be a Regular Expression or a string. If pattern is a Regular Expression or a string, str is divided where the pattern matches.
A regular expression is a special sequence of characters that helps you match or find other strings or sets of strings using a specialized syntax held in a pattern.
The general syntax for using the split method is string. split() . The place at which to split the string is specified as an argument to the method. The split substrings will be returned together in an array.
I think this would do it:
a.split(/\.(?=[\w])/) I don't know how much you know about regex, but the (?=[\w]) is a lookahead that says "only match the dot if the next character is a letter kind of character". A lookahead won't actually grab the text it matches. It just "looks". So the result is exactly what you're looking for:
> a.split(/\.(?=[\w])/) => ["foo", "bar", "size", "split('.')", "last"] If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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