Ruby Regexp group matching, assign variables on 1 line

Question

I'm currently trying to rexp a string into multiple variables. Example string:

ryan_string = "RyanOnRails: This is a test" 

I've matched it with this regexp, with 3 groups:

ryan_group = ryan_string.scan(/(^.*)(:)(.*)/i) 

Now to access each group I have to do something like this:

ryan_group[0][0] (first group) RyanOnRails ryan_group[0][1] (second group) : ryan_group[0][2] (third group) This is a test 

This seems pretty ridiculous and it feels like I'm doing something wrong. I would be expect to be able to do something like this:

g1, g2, g3 = ryan_string.scan(/(^.*)(:)(.*)/i) 

Is this possible? Or is there a better way than how I'm doing it?

Answer 1

You don't want scan for this, as it makes little sense. You can use String#match which will return a MatchData object, you can then call #captures to return an Array of captures. Something like this:

#!/usr/bin/env ruby  string = "RyanOnRails: This is a test" one, two, three = string.match(/(^.*)(:)(.*)/i).captures  p one   #=> "RyanOnRails" p two   #=> ":" p three #=> " This is a test" 

Be aware that if no match is found, String#match will return nil, so something like this might work better:

if match = string.match(/(^.*)(:)(.*)/i)   one, two, three = match.captures end 

Although scan does make little sense for this. It does still do the job, you just need to flatten the returned Array first. one, two, three = string.scan(/(^.*)(:)(.*)/i).flatten

Answer 2

You could use Match or =~ instead which would give you a single match and you could either access the match data the same way or just use the special match variables $1, $2, $3

Something like:

if ryan_string =~ /(^.*)(:)(.*)/i    first = $1    third = $3 end