Ruby: How to filter in a hash structure to get all the keys which are <>"1"?

Question

I want to find some elegant way to achieve this. Maybe like follwing:

hash={"1"=>"1","2"=>"2"}
r=[]
hash.each do |k,v|
    if k!="1"
       r<<k
    end
end
puts r

Any better way to achieve this?

Answer 1

You can use "array difference":

hash.keys - ['1']
#=> ["2"]