simpler way to modify a string

Question

I recently solved this problem, but felt there is a simpler way to do it. I'd like to use fewer lines of code than I am now. I'm new to ruby so if the answer is simple I'd love to add it to my toolbag. Thank you in advance.

goal: accept a word as an arg, and return the word with it's last vowel removed, if no vowels - return the original word

def hipsterfy(word)
    vowels = "aeiou"
    i = word.length - 1
    while i >= 0
        if vowels.include?(word[i])
            return word[0...i] + word[i+1..-1]
        end
        i -= 1
    end
    word
end

Answer 1

try this regex magic:

def hipsterfy(word)
  word.gsub(/[aeiou](?=[^aeiou]*$)/, "")
end

how does it work?

[aeiou] looks for a vowel., and ?=[^aeiou]*$ adds the constraint "where there is no vowel match in the following string. So the regex finds the last vowel. Then we just gsub the matched (last vowel) with "".