Ruby: How do I pass all parameters and blocks received by one method to another?

Question

I am writing a helper that adds an HTML attribute to a link_to tag in rails. So, my thinking is that my helper method should accept any parameters or blocks passed to it, call link_to with those same parameters, add it's attribute to what is returned, and return the result to the caller.

Like this:

def link_to(*args, &block)   ... rails code in link_to ... end  def myhelper(*args, &block) # Notice that at this point, 'args' has already   link_to()                 # become an array of arguments and 'block' has   ... my code ...           # already been turned into a Proc. end  myhelper() # Any arguments or blocks I pass with this call should make            # it all the way through to link_to. 

So, as you can see, there seems to be no way (that doesn't involve lots of code and conditional branching) to pass what myhelper has received to link_to without turning all of the parameters back into what they looked like before they got to my method.

Is there a more 'Ruby-like' solution to this problem?

Answer 1

You can use * and & in method calls to turn arrays back into lists of arguments and procs back into blocks. So you can just do this:

def myhelper(*args, &block)   link_to(*args, &block)   # your code end