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The first() is an inbuilt method in Ruby returns an array of first X elements. If X is not mentioned, it returns the first element only. Syntax: range1.first(X) Parameters: The function accepts X which is the number of elements from the beginning. Return Value: It returns an array of first X elements.
slice() is a method in Ruby that is used to return a sub-array of an array. It does this either by giving the index of the element or by providing the index position and the range of elements to return.
Either I don't understand your question, or Enumerable#find is the thing you were looking for.
use array detect method if you wanted to return first value where block returns true
[1,2,3,11,34].detect(&:even?) #=> 2
OR
[1,2,3,11,34].detect{|i| i.even?} #=> 2
If you wanted to return all values where block returns true then use select
[1,2,3,11,34].select(&:even?) #=> [2, 34]
Guess you just missed the find method in the docs:
my_array.find {|e| e.satisfies_condition? }
Do you need the object itself or do you just need to know if there is an object that satisfies. If the former then yes: use find:
found_object = my_array.find { |e| e.satisfies_condition? }
otherwise you can use any?
found_it = my_array.any? { |e| e.satisfies_condition? }
The latter will bail with "true" when it finds one that satisfies the condition. The former will do the same, but return the object.
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