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Now, This is the array,
[1,2,3,4,5,6,7,8,9] I want,
[1,2],[2,3],[3,4] upto [8,9] When I do, each_slice(2) I get,
[[1,2],[3,4]..[8,9]] Im currently doing this,
arr.each_with_index do |i,j| p [i,arr[j+1]].compact #During your arr.size is a odd number, remove nil. end Is there a better way??
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The "each" method in Ruby on Rails allows you to iterate over different objects inside an array-like structure.
Ruby | Array class first() function first() is a Array class method which returns the first element of the array or the first 'n' elements from the array.
split is a String class method in Ruby which is used to split the given string into an array of substrings based on a pattern specified. Here the pattern can be a Regular Expression or a string. If pattern is a Regular Expression or a string, str is divided where the pattern matches.
Ruby reads your mind. You want cons ecutive elements?
[1, 2, 3, 4, 5, 6, 7, 8, 9].each_cons(2).to_a # => [[1, 2], [2, 3], [3, 4], [4, 5], [5, 6], [6, 7], [7, 8], [8, 9]] .each_cons does exactly what you want.
[1] pry(main)> a = [1,2,3,4,5,6,7,8,9] => [1, 2, 3, 4, 5, 6, 7, 8, 9] [2] pry(main)> a.each_cons(2).to_a => [[1, 2], [2, 3], [3, 4], [4, 5], [5, 6], [6, 7], [7, 8], [8, 9]] If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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