Menu
Hi everyone I am currently doing a school project and even my teacher is stumped. In Canada the penny has been removed so now all purchases are rounded to either 0 or 5. For example 5.53 would become 5.55 and 5.52 would become 5.50. I am trying to get my program to round like this, but I can't figure out how. I know how to round to decimal places, but I don't know how to round to specifics like this. Any help would be appreciated!
Here is my code. The project is about making a program that a cashier would use in a coffee shop.
order = ['coffee', 'tea', 'hashbrown','jelly','cream','chocolate','glazed','sandwich','bagel','cookie','pannini']
quantity = ['0','0','0','0','0','0','0','0','0','0','0']
# coffee = $1
# Tea = $1.30
# hashbrown = $1.25
# all donuts = $1.50
# sandwich = $2.50
# bagel = $2
# cookie = $0.50
# pannini = $4
cashier = 1
total = 0
while cashier == 1:
print "What did the customer order?"
ordered = input ()
while ordered > 10 or ordered < 0:
print "Do you want to input a valid order?"
ordered = input ()
print "How many are being ordered?"
quantityorder = input ()
quantity[ordered] = quantityorder
print "Ordered",quantityorder,"",order[ordered],"!"
if ordered == 0:
ordered = 1.0
elif ordered == 1:
ordered = 1.30
elif ordered == 2:
ordered = 1.25
elif ordered == 3 or ordered == 4 or ordered == 5 or ordered == 6:
ordered = 1.50
elif ordered == 7:
ordered = 2.50
elif ordered == 8:
ordered = 2
elif ordered == 9:
ordered = 0.50
else:
ordered = 4.0
price = ordered * quantityorder
total = total + price
print "Anything else?"
cashier = input () #If the user inputs 1 then they can input another order if they didn't put in 1 then the program assumes that it is the end of a customers order
print "Your total is $", total * 1.13,"!"
total = total * 1.13
print
print "How much money was given?"
print
money = input ()* 1.0
while money < total:
print "Please input a valid number!"
money = input ()
print "The change should be $",money - total,"!"
883
Python has a built-in round() function that takes two numeric arguments, n and ndigits , and returns the number n rounded to ndigits . The ndigits argument defaults to zero, so leaving it out results in a number rounded to an integer.
Python: round() function Note: For the built-in types supporting round(), values are rounded to the closest multiple of 10 to the power minus ndigits; if two multiples are equally close, rounding is done toward the even choice (so, for example, both round(0.5) and round(-0.5) are 0, and round(1.5) is 2).
Practical Data Science using Python Python's round() function requires two arguments. First is the number to be rounded. Second argument decides the number of decimal places to which it is rounded. To round the number to 2 decimals, give second argument as 2.
This tortured me until I solved it. One rule I set for myself was NOT to use a case-by-case switch on modulo 5, but to use builtin functions. Nice puzzle. wim's "double it, round, then halve it" comment was close.
def nickelround(n):
N = int(n)
print "%0.2f" % (N + round((n - N) * 20) * 0.05)
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
