how can i round up a floating point number to the next integer value in Java? Suppose
2.1 -->3
3.001 -->4
4.5 -->5
7.9 -->8
You should look at ceiling rounding up in java's math packages: Math.ceil
EDIT: Added the javadoc for Math.ceil. It may be worth reading all the method in Math.
http://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#ceil%28double%29
public static double ceil(double a)
Returns the smallest (closest to negative infinity) double value that is greater than or equal to the argument and is equal to a mathematical integer. Special cases:
- If the argument value is already equal to a mathematical integer, then the result is the same as the argument.
- If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.
- If the argument value is less than zero but greater than -1.0, then the result is negative zero.
Note that the value of
Math.ceil(x)
is exactly the value of-Math.floor(-x)
.
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