Enum does not, in itself take any space, but in implementations that adhere to standard C making the enumerated variable an int, they do cost you one byte, if you otherwise would have used a char.
enums are not allocated in memory - they exist only on compilation stage. They only exist to tell compiler what value is Tuesday in ur example.
In Java, there should only be one instance of each of the values of your enum in memory. A reference to the enum then requires only the storage for that reference. Checking the value of an enum is as efficient as any other reference comparison.
In Java, an enum
is a full-blown class:
Java programming language enum types are much more powerful than their counterparts in other languages. The enum declaration defines a class (called an enum type). The enum class body can include methods and other fields.
In order to see the actual size of each enum
, let's make an actual enum
and examine the contents of the class
file it creates.
Let's say we have the following Constants
enum class:
public enum Constants {
ONE,
TWO,
THREE;
}
Compiling the above enum
and disassembling resulting class
file with javap
gives the following:
Compiled from "Constants.java"
public final class Constants extends java.lang.Enum{
public static final Constants ONE;
public static final Constants TWO;
public static final Constants THREE;
public static Constants[] values();
public static Constants valueOf(java.lang.String);
static {};
}
The disassembly shows that that each field of an enum
is an instance of the Constants
enum
class. (Further analysis with javap
will reveal that each field is initialized by creating a new object by calling the new Constants(String)
constructor in the static initialization block.)
Therefore, we can tell that each enum
field that we create will be at least as much as the overhead of creating an object in the JVM.
In Java, there should only be one instance of each of the values of your enum in memory. A reference to the enum then requires only the storage for that reference. Checking the value of an enum is as efficient as any other reference comparison.
You would only worry about this when storing large quantities of enums. For Java, you may be able to use an EnumSet in some cases. It uses a bit vector internally which is very space efficient and fast.
http://java.sun.com/j2se/1.5.0/docs/api/java/util/EnumSet.html
bool
might be implemented as a single byte, but typically in a structure it would be surrounded by other elements that have alignment requirements that would mean that the boolean would effectively be occupying at least as much space as an int
.
Modern processors load data from main memory as a whole cache line, 64 bytes. The difference between loading one byte from L1 cache and loading four bytes is negligible.
If you're trying to optimise for cache lines in a very high-performance application, then you might worry about how big your enum is, but generally I'd say it's clearer to define an enum than to use a boolean.
In Java, it would take more memory. In C++, it would take no memory than required for a constant of the same type (it's evaluated at compile-time and has no residual significance at runtime). In C++, this means that the default type for an enum will occupy the same space as an int.
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