RGB Int to RGB - Python

Question

How can I convert an RGB integer to the corresponding RGB tuple (R,G,B)? Seems simple enough, but I can't find anything on google.

I know that for every RGB (r,g,b) you have the integer n = r256^2 + g256 + b, how can I solve the reverse in Python, IE given an n, I need the r,g,b values.

Answer 1

I'm not a Python expert by all means, but as far as I know it has the same operators as C.

If so this should work and it should also be a lot quicker than using modulo and division.

Blue =  RGBint & 255 Green = (RGBint >> 8) & 255 Red =   (RGBint >> 16) & 255 

What it does it to mask out the lowest byte in each case (the binary and with 255.. Equals to a 8 one bits). For the green and red component it does the same, but shifts the color-channel into the lowest byte first.

Answer 2

From a RGB integer:

Blue =  RGBint mod 256 Green = RGBint / 256 mod 256 Red =   RGBint / 256 / 256 mod 256 

This can be pretty simply implemented once you know how to get it. :)

Upd: Added python function. Not sure if there's a better way to do it, but this works on Python 3 and 2.4

def rgb_int2tuple(rgbint):     return (rgbint // 256 // 256 % 256, rgbint // 256 % 256, rgbint % 256) 

There's also an excellent solution that uses bitshifting and masking that's no doubt much faster that Nils Pipenbrinck posted.