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Using AJAX I populate a DIV with a bunch of checkboxes (each with it's own unique ID). The IDs are "projectID1", "projectID2", "projectID3" and so on... I have given all checkboxes a class of "pChk".
My end goal is to show the DIV containing the Submit Button if ANY of the checkboxes are checked. The only time the DIV containing the Submit Button show be hidden is if all checkboxes are unchecked.
However the code I have come up with below shows/hides the Submit Button DIV for each checkbox instance. In other words, if I have three checkboxes CHECKED and I UNCHECK one of them, the Submit Button DIV get hidden.
Your expert advice is more than welcome!
function checkUncheck() { $('.pChk').click(function() { if (this.checked) { $("#ProjectListButton").show(); } else { $("#ProjectListButton").hide(); } }); } 
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In order to display data/content of a specific element by selecting the particular checkbox in jQuery we can use the toggle() method. The toggle() method is used to check the visibility of selected elements to toggle between hide() and show() for the selected elements.
To check whether a Checkbox has been checked, in jQuery, you can simply select the element, get its underlying object, instead of the jQuery object ( [0] ) and use the built-in checked property: let isChecked = $('#takenBefore')[0]. checked console. log(isChecked);
While this is old if someone comes across this again (via search). The correct answer with jQuery 1.7 onwards is now:
$('.pChk').click(function() { if( $(this).is(':checked')) { $("#ProjectListButton").show(); } else { $("#ProjectListButton").hide(); } }); I use jQuery prop
$('#yourCheckbox').change(function(){ if($(this).prop("checked")) { $('#showDiv').show(); } else { $('#hideDiv').hide(); } }); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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