reverse the position of integer digits?

Question

i have to reverse the position of integer like this

input = 12345

output = 54321

i made this but it gives wrong output e.g 5432

#include <iostream>
using namespace std;

int main(){
 int num,i=10;   
 cin>>num;   

 do{
    cout<< (num%i)/ (i/10);
    i *=10;
   }while(num/i!=0);

 return 0;
}

Answer 1

Here is a solution

    int num = 12345;
    int new_num = 0;
    while(num > 0)
    {
            new_num = new_num*10 + (num % 10);
            num = num/10;
    }
    cout << new_num << endl;

Answer 2

Your loop terminates too early. Change

}while(num/i!=0);

to

}while((num*10)/i!=0);

to get one more iteration, and your code will work.