Here's my PHP code called during jQuery AJAX call:
<?php
    include '../code_files/conn.php';
    $conn = new Connection();
    $query = 'SELECT Address_1, Address_2, City, State, OfficePhone1, OfficePhone2, Fax1, Fax2, Email_1, Email_2 
              FROM clients WHERE ID = ?';
    $conn->mysqli->stmt_init();
    $stmt = $conn->mysqli->prepare($query);
    $stmt->bind_param('s', $_POST['ID']);
    $stmt->execute();
    $result = $stmt->get_result();
    $row = $result->fetch_assoc();
    echo json_encode($row);
?>
And the client-side code is:
$.post(url, {ID:$('#ddlClients').val()},
        function(Result){
            // Result
        }
      );
The AJAX call is successfully completed. I get the value of Result as
"{"Address_1":"Divisional Office 1","Address_2":"The XYZ Road",.....and so on
What I want is to be able to use the values returned like Result.Address_1, Result.Address_2 and so on. But I can't do it using the above code. I tried using $row = $result->fetch_object() and $row = $result->fetch_array(), but no use.
And I know that this can be done by this code on the server side:
$row = $result->fetch_assoc();
$retVal = array("Address_1"=>$row['Address_1'], "Address_2"=>$row['Address_2'].......);
echo json_encode($retVal);
or
$row = $result->fetch_object();
$retVal = array("Address_1"=>$row->Address_1, "Address_2"=>$row->Address_2.......);
echo json_encode($retVal);
Is there a way to send the $row directly to the client side JavaScript and ready to be used as JSON object, without manually creating an array first? 
On document ready state send an AJAX GET request to 'ajaxfile. php' . Loop through all response values and append a new row to <table id='userTable'> on AJAX successfully callback. Note – For handling JSON response you have to set dataType: 'JSON' while sending AJAX request.
You can simply use the json_encode() function to return JSON response from a PHP script. Also, if you're passing JSON data to a JavaScript program, make sure set the Content-Type header.
By using the jQuery ajax method we can call them or we can say that we can request the different types of text and post such as HTML, XML, and JSON from the remote server as well as it uses the get and post method that is HTTP protocol.
The response you are getting from your PHP script is in plain text. You can however parse that string into an object using $.parseJSON in your callback function:
$.ajax({
    url      : url,//note that this is setting the `url` property to the value of the `url` variable
    data     : {ID:$('#ddlClients').val()},
    type     : 'post',
    success  : function(Result){
            var myObj = $.parseJSON(Result);
            //you can now access data like this:
            //myObj.Address_1
        }
    }
  );
You can let jQuery do this for you by setting the dataType property for your AJAX call to json:
$.ajax({
    url      : url//note that this is setting the `url` property to the value of the `url` variable
    data     : {ID:$('#ddlClients').val()},
    dataType : 'json',
    type     : 'post',
    success  : function(Result){
            //you can now access data like this:
            //Result.Address_1
        }
    }
  );
The above examples expect that the response from the server to be in this format (from your question):
"{"Address_1":"Divisional Office 1","Address_2":"The XYZ Road"}
                        In your $.post call, the last argument could be the data-type: json:
$.post(url, {ID:$('#ddlClients').val()},
    function(Result){
        alert(Result.Address_1);
    },'json'
 );
Everything should work then, as it looks like you are doing everything right.
json_encode accepts objects, so there's no need to do that automatic array-building.:
$row = $result->fetch_object();
echo json_encode($row);
It's as simple as that!
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