The metacharacter “\s” matches spaces and + indicates the occurrence of the spaces one or more times, therefore, the regular expression \S+ matches all the space characters (single or multiple). Therefore, to replace multiple spaces with a single space.
Continuing with that same thought, if your string with spaces is already stored in a variable, you can simply use echo unquoted within command substitution to have bash remove the additional whitespace for your, e.g. $ foo="too many spaces."; bar=$(echo $foo); echo "$bar" too many spaces.
Use JavaScript's string. replace() method with a regular expression to remove extra spaces. The dedicated RegEx to match any whitespace character is \s . Expand the whitespace selection from a single space to multiple using the \s+ RegEx.
Use It is the entity used to represent a non-breaking space.
Something like this:
var s = " a b c ";
console.log(
s.replace(/\s+/g, ' ')
)
You can augment String to implement these behaviors as methods, as in:
String.prototype.killWhiteSpace = function() {
return this.replace(/\s/g, '');
};
String.prototype.reduceWhiteSpace = function() {
return this.replace(/\s+/g, ' ');
};
This now enables you to use the following elegant forms to produce the strings you want:
"Get rid of my whitespaces.".killWhiteSpace();
"Get rid of my extra whitespaces".reduceWhiteSpace();
using a regular expression with the replace function does the trick:
string.replace(/\s/g, "")
var s = ' a b word word. word, wordword word ';
// with ES5:
s = s.split(' ').filter(function(n){ return n != '' }).join(' ');
console.log(s); // "a b word word. word, wordword word"
// or ES2015:
s = s.split(' ').filter(n => n).join(' ');
console.log(s); // "a b word word. word, wordword word"
Can even substitute filter(n => n)
with .filter(String)
It splits the string by whitespaces, remove them all empty array items from the array (the ones which were more than a single space), and joins all the words again into a string, with a single whitespace in between them.
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