Is there an efficient method to remove a range - say the tail - of X elements from a List
, e.g. LinkedList
in Java?
It is obviously possible to remove the last elements one by one, which should result in O(X) level performance. At least for LinkedList
instances it should be possible to have O(1) performance (by setting the references around the first element to be removed and setting the head/tail references). Unfortunately I don't see any method within List
or LinkedList
to remove the last elements all at once.
Currently I am thinking of replacing the list by using List.subList()
but I'm not sure if that has equal performance. At least it would be more clear within the code, on the other hand I would loose the additional functionality that LinkedList
provides.
I'm mainly using the List as a stack, for which LinkedList
seems to be the best option, at least regarding semantics.
The removeRange() method is used to removes all elements within the specified range from a ArrayList object. It shifts any succeeding elements to the left (reduces their index). This call shortens the list by (toIndex - fromIndex) elements.
pop() function. The simplest approach is to use the list's pop([i]) function, which removes an element present at the specified position in the list. If we don't specify any index, pop() removes and returns the last element in the list.
Python3. Method 3: Using pop() method: the pop() method will remove the last element from the list, So to remove last k elements from the python list, we need to perform the pop() operation k times.
Using del Another efficient, yet simple approach to delete the last element of the list is by using the del statement. The del operator deletes the element at the specified index location from the list. To delete the last element, we can use the negative index -1.
subList(list.size() - N, list.size()).clear()
is the recommended way to remove the last N
elements. Indeed, the Javadoc for subList
specifically recommends this idiom:
This method eliminates the need for explicit range operations (of the sort that commonly exist for arrays). Any operation that expects a list can be used as a range operation by passing a subList view instead of a whole list. For example, the following idiom removes a range of elements from a list:
list.subList(from, to).clear();
Indeed, I suspect that this idiom might be more efficient (albeit by a constant factor) than calling removeLast()
N
times, just because once it finds the N
th-to-last node, it only needs to update a constant number of pointers in the linked list, rather than updating the pointers of each of the last N
nodes one at a time.
Be aware that subList()
returns a view of the original list, meaning:
LinkedList
- it's an inner implementation of List
that's not serializableAnyway, using either removeFirst()
or removeLast()
should be efficient enough, because popping the first or last element of a linked list in Java is an O(1)
operation - internally, LinkedList
holds pointers to both ends of the list and removing either one is as simple as moving a pointer one position.
For removing m
elements at once, you're stuck with O(m)
performance with a LinkedList
, although strangely enough an ArrayList
might be a better option, because removing elements at the end of an ArrayList
is as simple as moving an index pointer (denoting the end of the array) one position to its left, and no garbage nodes are left dangling as is the case with a LinkedList
. The best choice? try both approaches, profile them and let the numbers speak for themselves.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With