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You can use Python's regular expressions to remove the first n characters from a string, using re's . sub() method. This is accomplished by passing in a wildcard character and limiting the substitution to a single substitution.
Strings are immutable in JavaScript. Alternatively, you can use the slice() method. Use the String. slice() method to remove the first N characters from a string, e.g. const result = str.
To remove the first 2 characters from a string, use the slice method, passing it 2 as a parameter, e.g. str. slice(2) . The slice method returns a new string containing the specified portion of the original string.
>>> text = 'lipsum'
>>> text[3:]
'sum'
See the official documentation on strings for more information and this SO answer for a concise summary of the notation.
Another way (depending on your actual needs): If you want to pop the first n characters and save both the popped characters and the modified string:
s = 'lipsum'
n = 3
a, s = s[:n], s[n:]
print(a)
# lip
print(s)
# sum
>>> x = 'lipsum'
>>> x.replace(x[:3], '')
'sum'
Use del.
Example:
>>> text = 'lipsum'
>>> l = list(text)
>>> del l[3:]
>>> ''.join(l)
'sum'
Example to show last 3 digits of account number.
x = '1234567890'
x.replace(x[:7], '')
o/p: '890'
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