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Use datetime. strftime(format) to convert a datetime object into a string as per the corresponding format . The format codes are standard directives for mentioning in which format you want to represent datetime. For example, the %d-%m-%Y %H:%M:%S codes convert date to dd-mm-yyyy hh:mm:ss format.
Let's see how to actually convert a String to a local date and time data type: Parse the API call: If the String value that we need to convert to the Date-time type is of ISO-801 format then we can simply call DateFormat and SimpleDateFormat classes using parse() methods.
I assume I have import datetime before running each of the lines of code below
datetime.datetime.strptime("2013-1-25", '%Y-%m-%d').strftime('%m/%d/%y')
prints "01/25/13".
If you can't live with the leading zero, try this:
dt = datetime.datetime.strptime("2013-1-25", '%Y-%m-%d')
print '{0}/{1}/{2:02}'.format(dt.month, dt.day, dt.year % 100)
This prints "1/25/13".
EDIT: This may not work on every platform:
datetime.datetime.strptime("2013-1-25", '%Y-%m-%d').strftime('%m/%d/%y')
If you can live with 01 for January instead of 1, then try...
d = datetime.datetime.strptime("2013-1-25", '%Y-%m-%d')
print datetime.date.strftime(d, "%m/%d/%y")
You can check the docs for other formatting directives.
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