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I've been whittling down my grep output (which comes down to a listing of numbers that I intend to associate with other fields.) My problem is that numbers above 999 have commas in them, and I'm wondering how to print the output with out the commas.
so instead of the output being:
1,200,300 it would just be:
1200300 Any suggestions for an additional pipe command that I could add?
Thanks
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The most simple way to exclude lines with a string or syntax match is by using grep and the -v flag. The output will be the example. txt text file but excluding any line that contains a string match with “ThisWord”. Use whichever works best for your particular workflow.
Remove Character from String Using cut Cut is a command-line tool commonly used to extract a portion of text from a string or file and print the result to a standard output. You can also use this command for removing characters from a string.
In this method, you have to use the rev command. The rev command is used to reverse the line of string characterwise. Here, the rev command will reverse the string, and then the -c option will remove the first character. After this, the rev command will reverse the string again and you will get your output.
Exclude Words and Patterns By default, grep is case-sensitive. This means that the uppercase and lowercase characters are treated as distinct. To ignore the case when searching, invoke grep with the -i option. If the search string includes spaces, you need to enclose it in single or double quotation marks.
Try this
< your command > | tr -d ',' tr will remove all commas
194
< your command > | sed -e 's/,//g' This will replace all commas with "nothing" without changing anything else.
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