I have a data.frame with a grouping variable, and some NAs in the value column.
df = data.frame(group=c(1,1,2,2,2,2,2,3,3), value1=1:9, value2=c(NA,4,9,6,2,NA,NA,1,NA))
I can use zoo::na.trim
to remove NA at the end of a column: this will remove the last line of the data.frame:
library(zoo)
library(dplyr)
df %>% na.trim(sides="right")
Now I want to remove the trailing NAs by group; how can I achieve this using dplyr?
Expected output for value2 column: c(NA, 4,9,6,2,1)
You could write a little helper function that checks for trailing NA
s of a vector and then use group_by
and filter
.
f <- function(x) { rev(cumsum(!is.na(rev(x)))) != 0 }
library(dplyr)
df %>%
group_by(group) %>%
filter(f(value2))
# A tibble: 6 x 3
# Groups: group [3]
group value1 value2
<dbl> <int> <dbl>
1 1 1 NA
2 1 2 4
3 2 3 9
4 2 4 6
5 2 5 2
6 3 8 1
edit
If we need to remove both leading and trailing zero we need to extend that function a bit.
f1 <- function(x) { cumsum(!is.na(x)) != 0 & rev(cumsum(!is.na(rev(x)))) != 0 }
Given df1
df1 = data.frame(group=c(1,1,2,2,2,2,2,3,3), value1=1:9, value2=c(NA,4,9,NA,2,NA,NA,1,NA))
df1
# group value1 value2
#1 1 1 NA
#2 1 2 4
#3 2 3 9
#4 2 4 NA
#5 2 5 2
#6 2 6 NA
#7 2 7 NA
#8 3 8 1
#9 3 9 NA
We get this result
df1 %>%
group_by(group) %>%
filter(f1(value2))
# A tibble: 5 x 3
# Groups: group [3]
group value1 value2
<dbl> <int> <dbl>
1 1 2 4
2 2 3 9
3 2 4 NA
4 2 5 2
5 3 8 1
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With