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I have following string vector:
EC02 502R 603 515 602
KL07 601 511R 505R 506R 503
508 514 501 509R 510 501R
512R 516 507 604 502 601R
SPK01 504 504R ACK01 503R 508R
507R ACK03 513 EC01 506 ECH01
ACK02 SPK02 509 511 512 505
KA01 RS01 510R SKL01 SPK03 603R
602R 604R 513R AECH01 ER03 AECH02
RS02 514R ER01 RH01 AR05 RH02
515R ER02 M01
I want to replace 502R to 502, 501R to 501, 503R to 503 and so on...
Only character R has to be replaced which is occurring at the end of the string.
How can I do it with gsub?
851
Using 'str. replace() , we can replace a specific character. If we want to remove that specific character, replace that character with an empty string. The str. replace() method will replace all occurrences of the specific character mentioned.
The idea is to use the deleteCharAt() method of StringBuilder class to remove first and the last character of a string. The deleteCharAt() method accepts a parameter as an index of the character you want to remove.
Use the deleteCharAt Method to Remove a Character From String in Java. The deleteCharAt() method is a member method of the StringBuilder class that can also be used to remove a character from a string in Java.
If you have a string vector and want to replace the last R character from it you can use sub. $ here ensures that the R is the last character in your vector.
sub("R$", "", str)
#[1] "EC02" "502" "603" "5RFRS"
data
str <- c("EC02", "502R","603", "5RFRS)
I have used sub here instead of gsub. sub replaces only first occurrence of the pattern whereas gsub replaces all occurrences of the pattern though in this case the usage of sub/gsub wouldn't matter.
178
lapply( dfrm, function(col_) {gsub( "R","",col_)} )
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