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Remove null properties of an object sent to Json MVC

namespace Booking.Areas.Golfy.Models
{
    public class Time
    {
        public string   time            { get; set; }
        public int      holes           { get; set; }
        public int      slots_available { get; set; }
        public decimal? price           { get; set; }
        public int?     Nextcourseid    { get; set; }

        public bool ShouldSerializeNextcourseid
        {
            get
            {
                return this.Nextcourseid != null;
            }
        }

        public bool? allow_extra { get; set; }

        public bool ShouldSerializeallow_extra
        {
            get
            {
                return this.allow_extra != null;
            }
        }
    }
}


namespace Booking.Areas.Golfy.Controllers
{
    public class TeetimesController : Controller
    {
        //
        // GET: /Golfy/Teetimes/
        public ActionResult Index(
            string date,
            int?   courseid = null,
            int?   clubid = null,
            int?   holes = null,
            int?   available = null,
            int?   prices = null
        )
        {
            var DateFrom = DateTime.ParseExact(date, "yyyy-MM-dd", CultureInfo.InvariantCulture);

            Teetimes r = BookingManager.GetBookings(new Code.Classes.Params.ParamGetBooking()
            {
                ClubID = clubid
                , DateFrom = DateFrom
                , DateTo = DateFrom.AddDays(1)
                , GroundID = courseid
            });

            return Json(r, JsonRequestBehavior.AllowGet);
        }
    }
}

The webservice above returns a json string with several intance of Time.

I'd like properties Nextcourseid and allow_extra to be left out of the output when their values are null.

I tried ShouldSerializeXxx but it doesn't seems to work.
FYI: I also tried [ScriptIgnore] which work but isn't conditional.

like image 680
Serge Avatar asked Jan 07 '14 14:01

Serge


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How to Remove null fields from json response?

You can ignore null fields at the class level by using @JsonInclude(Include. NON_NULL) to only include non-null fields, thus excluding any attribute whose value is null. You can also use the same annotation at the field level to instruct Jackson to ignore that field while converting Java object to json if it's null.

How to avoid null value in json?

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1 Answers

You can't use the default Json ActionResult to remove null properties.

You can take a look at JSON.NET, it has an attribute that you can set to remove the property if it is null

[JsonProperty(NullValueHandling=NullValueHandling.Ignore)]

Or if you don't want to use other libraries you can create your own json custom ActionResult and register a new converter for the default JavaScriptSerializer, like this:

public class JsonWithoutNullPropertiesResult : ActionResult
{
    private object Data { get; set; }

    public JsonWithoutNullPropertiesResult(object data)
    {
        Data = data;
    }

    public override void ExecuteResult(ControllerContext context)
    {
        HttpResponseBase response = context.HttpContext.Response;
        response.ContentType = "application/x-javascript";
        response.ContentEncoding = Encoding.UTF8;

        if (Data != null)
        {
            JavaScriptSerializer serializer = new JavaScriptSerializer();
            serializer.RegisterConverters(new[] { new NullPropertiesConverter() });
            string ser = serializer.Serialize(Data);
            response.Write(ser);
        }
    }
}

public class NullPropertiesConverter : JavaScriptConverter
{
    public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
    {
        var toSerialize = new Dictionary<string, object>();

        foreach (var prop in obj.GetType()
                                .GetProperties(BindingFlags.Instance | BindingFlags.Public)
                                .Select(p => new
                                {
                                    Name = p.Name,
                                    Value = p.GetValue(obj)
                                })
                                .Where(p => p.Value != null))
        {
            toSerialize.Add(prop.Name, prop.Value);
        }

        return toSerialize;
    }

    public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
    {
        throw new NotImplementedException();
    }

    public override IEnumerable<Type> SupportedTypes
    {
        get { return GetType().Assembly.GetTypes(); }
    }
}

And now in your view:

public ActionResult Index()
{
    Teetimes r = BookingManager.GetBookings();
    return new JsonWithoutNullPropertiesResult(t);
}
like image 135
Davor Zlotrg Avatar answered Oct 05 '22 22:10

Davor Zlotrg