Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Remove end of line characters from Java string

People also ask

How do I remove a trailing character from a string in Java?

Using StringBuildersetLength() instead of StringBuilder. deleteCharAt() when we remove trailing zeroes because it also deletes the last few characters and it's more performant.


Regex with replaceAll.

public class Main
{
    public static void main(final String[] argv) 
    {
        String str;

        str = "hello\r\njava\r\nbook";
        str = str.replaceAll("(\\r|\\n)", "");
        System.out.println(str);
    }
}

If you only want to remove \r\n when they are pairs (the above code removes either \r or \n) do this instead:

str = str.replaceAll("\\r\\n", "");

If you want to avoid the regex, or must target an earlier JVM, String.replace() will do:

str=str.replace("\r","").replace("\n","");

And to remove a CRLF pair:

str=str.replace("\r\n","");

The latter is more efficient than building a regex to do the same thing. But I think the former will be faster as a regex since the string is only parsed once.


public static void main(final String[] argv) 
{
    String str;

    str = "hello\r\n\tjava\r\nbook";
    str = str.replaceAll("(\\r|\\n|\\t)", "");
    System.out.println(str);
}

It would be useful to add the tabulation in regex too.


Given a String str:

str = str.replaceAll("\\\\r","")
str = str.replaceAll("\\\\n","")