Given an unknown amount of lists, each with an unknown length, I need to generate a singular list with all possible unique combinations. For example, given the following lists:
X: [A, B, C]
Y: [W, X, Y, Z]
Then I should be able to generate 12 combinations:
[AW, AX, AY, AZ, BW, BX, BY, BZ, CW, CX, CY, CZ]
If a third list of 3 elements were added, I'd have 36 combinations, and so forth.
Any ideas on how I can do this in Java?
(pseudo code would be fine too)
Add a Custom Column to and name it List1. Enter the formula =List1. Expand out the new List1 column and then Close & Load the query to a table. The table will have all the combinations of items from both lists and we saved on making a custom column in List1 and avoided using a merge query altogether!
The unique combination of two lists in Python can be formed by pairing each element of the first list with the elements of the second list. Method 1 : Using permutation() of itertools package and zip() function. Approach : Import itertools package and initialize list_1 and list_2.
You need recursion:
Let's say all your lists are in lists
, which is a list of lists. Let result
be the list of your required permutations. You could implement it like this:
void generatePermutations(List<List<Character>> lists, List<String> result, int depth, String current) {
if (depth == lists.size()) {
result.add(current);
return;
}
for (int i = 0; i < lists.get(depth).size(); i++) {
generatePermutations(lists, result, depth + 1, current + lists.get(depth).get(i));
}
}
The ultimate call will be like this:
generatePermutations(lists, result, 0, "");
This operation is called cartesian product. Guava provides an utility function for that: Lists.cartesianProduct
This topic came in handy. I've rewritten the previous solution fully in Java and more user friendly. Furthermore, I use collections and generics for more flexibility:
/**
* Combines several collections of elements and create permutations of all of them, taking one element from each
* collection, and keeping the same order in resultant lists as the one in original list of collections.
*
* <ul>Example
* <li>Input = { {a,b,c} , {1,2,3,4} }</li>
* <li>Output = { {a,1} , {a,2} , {a,3} , {a,4} , {b,1} , {b,2} , {b,3} , {b,4} , {c,1} , {c,2} , {c,3} , {c,4} }</li>
* </ul>
*
* @param collections Original list of collections which elements have to be combined.
* @return Resultant collection of lists with all permutations of original list.
*/
public static <T> Collection<List<T>> permutations(List<Collection<T>> collections) {
if (collections == null || collections.isEmpty()) {
return Collections.emptyList();
} else {
Collection<List<T>> res = Lists.newLinkedList();
permutationsImpl(collections, res, 0, new LinkedList<T>());
return res;
}
}
/** Recursive implementation for {@link #permutations(List, Collection)} */
private static <T> void permutationsImpl(List<Collection<T>> ori, Collection<List<T>> res, int d, List<T> current) {
// if depth equals number of original collections, final reached, add and return
if (d == ori.size()) {
res.add(current);
return;
}
// iterate from current collection and copy 'current' element N times, one for each element
Collection<T> currentCollection = ori.get(d);
for (T element : currentCollection) {
List<T> copy = Lists.newLinkedList(current);
copy.add(element);
permutationsImpl(ori, res, d + 1, copy);
}
}
I'm using guava library for collections creation.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With